Optimizing Caloric Intake: Analysis of Food Items A, B, C, and D to Meet Energy Requirements for Improved Health.

A patient is on a 2,000 kcal diet but is meeting only 80 percent of his total energy need. Which of the following food items could provide adequate calories for the remaining 20 percent?Food item A (20 grams of fat, 20 grams of carbohydrate, and 35 grams of protein)Food item B (10 grams of fat, 20 grams of carbohydrate, and 35 grams of protein)Food item C (20 grams of fat, 10 grams of carbohydrate, and 35 grams of protein)Food item D (20 grams of fat, 20 grams of carbohydrate, and 25 grams of protein)

Food item A (20 grams of fat, 20 grams of carbohydrate, and 35 grams of protein)

To determine which food item could provide adequate calories for the remaining 20 percent, we need to calculate the total calories provided by each food item and compare it to the patient’s energy needs.

Here is how to calculate the total calories provided by each food item:
Food item A:
– 20 grams of fat x 9 kcal per gram = 180 kcal
– 20 grams of carbohydrate x 4 kcal per gram = 80 kcal
– 35 grams of protein x 4 kcal per gram = 140 kcal
Total = 400 kcal

Food item B:
– 10 grams of fat x 9 kcal per gram = 90 kcal
– 20 grams of carbohydrate x 4 kcal per gram = 80 kcal
– 35 grams of protein x 4 kcal per gram = 140 kcal
Total = 310 kcal

Food item C:
– 20 grams of fat x 9 kcal per gram = 180 kcal
– 10 grams of carbohydrate x 4 kcal per gram = 40 kcal
– 35 grams of protein x 4 kcal per gram = 140 kcal
Total = 360 kcal

Food item D:
– 20 grams of fat x 9 kcal per gram = 180 kcal
– 20 grams of carbohydrate x 4 kcal per gram = 80 kcal
– 25 grams of protein x 4 kcal per gram = 100 kcal
Total = 360 kcal

The patient needs 2,000 kcal per day, but is only meeting 80% of his energy needs, which is 1,600 kcal per day (2,000 kcal x 0.80 = 1,600 kcal). To determine how many calories are needed to meet the remaining 20%, we multiply 1,600 kcal by 0.20, which equals 320 kcal (1,600 kcal x 0.20 = 320 kcal).

Comparing the total calories provided by each food item to the 320 kcal needed, it is clear that Food item A, with a total of 400 kcal, would provide adequate calories for the remaining 20% of the patient’s energy needs (320 kcal). Therefore, Food item A is the best choice for meeting the patient’s energy needs.

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