Cl2 excess/ OH- will remove _______
two OH’s syn
In the presence of chlorine (Cl2) in excess and hydroxide ions (OH-), the substance that will be removed is phenol. This reaction is known as the Gattermann-Chloromethylation reaction. In this reaction, phenol will undergo chloromethylation in the presence of formaldehyde and HCl, forming benzaldehyde. Benzaldehyde will then react with Cl2 and OH-, forming benzoic acid and HCl.
So, in summary, the Cl2 excess/OH- will remove phenol by converting it into benzoic acid through the Gattermann-Chloromethylation reaction.
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