An administrator wants to create four subnetworks from the network address 192.168.1.0/24. What is the network address and subnet mask of the second useable subnet? subnetwork 192.168.1.64subnet mask 255.255.255.192 subnetwork 192.168.1.32subnet mask 255.255.255.240 subnetwork 192.168.1.64subnet mask 255.255.255.240 subnetwork 192.168.1.128subnet mask 255.255.255.192 subnetwork 192.168.1.8subnet mask 255.255.255.224
To create four subnetworks from the network address 192.168.1.0/24, we need to borrow bits from the host portion of the IP address.
First, let’s determine how many subnets we need. In this case, we need four subnets. Since four is a power of 2 (2^2 = 4), we will borrow 2 bits for subnetting.
The original network address is 192.168.1.0/24, which means the subnet mask is 255.255.255.0. By borrowing 2 bits, we increase the subnet mask to 255.255.255.192.
Let’s calculate the subnetworks with their corresponding subnet masks:
1. Subnetwork 1: 192.168.1.0/26 (subnet mask: 255.255.255.192)
2. Subnetwork 2: 192.168.1.64/26 (subnet mask: 255.255.255.192)
3. Subnetwork 3: 192.168.1.128/26 (subnet mask: 255.255.255.192)
4. Subnetwork 4: 192.168.1.192/26 (subnet mask: 255.255.255.192)
Therefore, the network address and subnet mask of the second usable subnet would be:
Network address: 192.168.1.64
Subnet mask: 255.255.255.192
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