An organization is assigned an IPv6 address block of 2001:db8:0:ca00::/56. How many subnets can be created without using bits in the interface ID space?
4,722,366,482,869,645,213,696
To determine the number of subnets that can be created from an IPv6 address block without using bits in the interface ID space, we need to analyze the given subnet mask.
In this case, the given IPv6 address block is 2001:db8:0:ca00::/56.
The /56 signifies that the first 56 bits of the address are reserved for the network portion, while the remaining 128 – 56 = 72 bits are used for the interface ID portion.
Since we are not allowed to use any bits in the interface ID space, all 72 bits must be set to zero.
Now, let’s calculate the number of subnets that can be created.
The formula to calculate the number of subnets is 2 ^(number of bits borrowed).
In this case, all 72 bits are borrowed, so the number of subnets is 2^72.
Calculating 2^72, we get a very large number:
4,722,366,482,869,645,213,696 subnets.
Therefore, without using bits in the interface ID space, an organization can create a staggering 4,722,366,482,869,645,213,696 subnets from the given IPv6 address block.
More Answers:
[next_post_link]