cot(x)dx
To integrate cot(x)dx, we can use a trigonometric identity that states:
cot(x) = 1/tan(x)
So, we can rewrite the integral as:
∫ cot(x)dx = ∫(1/tan(x))dx
Next, we can substitute tan(x) with its equivalent form of sin(x)/cos(x):
∫(1/(sin(x)/cos(x)))dx
Simplifying further, we get:
∫(cos(x)/sin(x))dx
To solve this integral, we can use a u-substitution
To integrate cot(x)dx, we can use a trigonometric identity that states:
cot(x) = 1/tan(x)
So, we can rewrite the integral as:
∫ cot(x)dx = ∫(1/tan(x))dx
Next, we can substitute tan(x) with its equivalent form of sin(x)/cos(x):
∫(1/(sin(x)/cos(x)))dx
Simplifying further, we get:
∫(cos(x)/sin(x))dx
To solve this integral, we can use a u-substitution. Let u = sin(x), then du/dx = cos(x) dx. Rearrange this equation to solve for dx: dx = du/cos(x).
Substituting these values into the integral, we get:
∫(1/u)(du/cos(x))
Now, we can cancel out the cos(x) terms:
∫(1/u)du
This integral can be solved easily:
∫(1/u)du = ln|u| + C
Substituting u back in terms of x, we have:
ln|sin(x)| + C
Therefore, the final answer to ∫ cot(x)dx is ln|sin(x)| + C, where C is the constant of integration.
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