ddx tanx
To find the derivative of tan(x) with respect to x (ddx tan(x)), we can use the quotient rule
To find the derivative of tan(x) with respect to x (ddx tan(x)), we can use the quotient rule.
The quotient rule states that if you have a function u(x) = f(x) / g(x), the derivative of u(x) with respect to x is given by:
u'(x) = [f'(x) * g(x) – f(x) * g'(x)] / [g(x)]^2
In this case, f(x) = sin(x) and g(x) = cos(x).
We’ll start by finding f'(x) and g'(x):
f'(x) = d/dx (sin(x)) = cos(x)
g'(x) = d/dx (cos(x)) = -sin(x)
Now, we can substitute these values into the quotient rule formula:
ddx tan(x) = [cos(x) * cos(x) – sin(x) * (-sin(x))] / [cos(x)]^2
Simplifying further:
ddx tan(x) = [cos^2(x) + sin^2(x)] / cos^2(x)
Using the trigonometric identity sin^2(x) + cos^2(x) = 1:
ddx tan(x) = 1 / cos^2(x)
Since cos^2(x) is equivalent to sec^2(x), we can rewrite the derivative as:
ddx tan(x) = 1 / sec^2(x)
And since sec^2(x) is equal to 1/cos^2(x), the derivative simplifies to:
ddx tan(x) = cos^2(x)
Therefore, the derivative of tan(x) with respect to x is cos^2(x).
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