1+tan^2x
sec^2x
We know that tan^2x + 1 = sec^2x.
Rearrange this equation to obtain 1 + tan^2x on one side:
tan^2x + 1 = sec^2x
tan^2x = sec^2x – 1
tan^2x = (1/cos^2x) – 1
Now substitute 1/cos^2x into the equation:
tan^2x = (1/cos^2x) – 1
tan^2x = (1 – cos^2x) / cos^2x
We know that 1 – cos^2x = sin^2x, so we can substitute that in:
tan^2x = (1 – cos^2x) / cos^2x
tan^2x = sin^2x / cos^2x
Finally, remember that tanx = sinx/cosx, so substitute that in:
tan^2x = sin^2x / cos^2x
tan^2x = (tanx)^2
Therefore,
1 + tan^2x = 1 + (tanx)^2
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