Derivative of Tangent Function (tan(x)) | Step-by-Step Guide and Simplified Expression

d/dx tanx

To find the derivative of the tangent function (tan(x)), we can use the quotient rule

To find the derivative of the tangent function (tan(x)), we can use the quotient rule. Before applying the quotient rule, let’s rewrite tan(x) as sin(x)/cos(x).

The quotient rule states that if we have a function f(x) = g(x)/h(x), then the derivative f'(x) is given by:

f'(x) = (g'(x) * h(x) – g(x) * h'(x)) / (h(x))^2

In this case, g(x) = sin(x) and h(x) = cos(x). So applying the quotient rule, we have:

(tan(x))’ = [(sin(x))’ * cos(x) – sin(x) * (cos(x))’] / (cos(x))^2

Now let’s find the derivatives of sin(x) and cos(x):

(sin(x))’ = cos(x)
(cos(x))’ = -sin(x)

Substituting these derivatives back into our expression:

(tan(x))’ = (cos(x) * cos(x) – sin(x) * (-sin(x))) / (cos(x))^2
= (cos^2(x) + sin^2(x)) / (cos^2(x))
= 1 / (cos^2(x))

Now, we can simplify our answer by using the identity cos^2(x) = 1 – sin^2(x):

(tan(x))’ = 1 / (1 – sin^2(x))

Finally, we can use the identity 1 – sin^2(x) = cos^2(x) to simplify even more:

(tan(x))’ = 1 / cos^2(x) = sec^2(x)

Therefore, the derivative of tan(x) with respect to x is sec^2(x), where sec(x) represents the secant function.

More Answers:
Understanding the Sine Function | Finding the Value of sin(π/3)
Finding the Value of tan(π/3) and Understanding the Tangent Function in Trigonometry
Evaluating cos(π/3) Using the Unit Circle and Special Angle Values in Trigonometry

Error 403 The request cannot be completed because you have exceeded your quota. : quotaExceeded

Share:

Recent Posts