Antiderivative csc^2x
To find the antiderivative of csc^2x, we can use a technique called integration by substitution
To find the antiderivative of csc^2x, we can use a technique called integration by substitution.
Let’s start by recalling the identity: csc^2x = 1 + cot^2x.
Now, let’s rewrite the expression of the antiderivative: ∫csc^2x dx.
We can rewrite csc^2x as (1 + cot^2x).
So, our integral becomes: ∫(1 + cot^2x) dx.
Now, we can split the integral into two parts: ∫1 dx + ∫cot^2x dx.
The integral of 1 with respect to x is simply x + C1, where C1 is the constant of integration.
Now, we are left with the second integral: ∫cot^2x dx.
To solve this integral, we can use the trigonometric identity: cot^2x = csc^2x – 1.
So, our integral becomes: ∫(csc^2x – 1) dx.
Distributing the integral: ∫csc^2x dx – ∫1 dx.
The first integral is what we initially wanted to solve, which is the antiderivative of csc^2x. The second integral is just x.
Therefore, the second integral is x and the first integral, according to our solved identity, is -cotx.
So, the final answer is: x – cotx + C2, where C2 is the constant of integration.
In summary, the antiderivative of csc^2x is x – cotx + C, where C is the constant of integration.
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