Use the confidence level and sample data to find a confidence interval for estimating the population. Round your answer to the same number of decimal places as the sample mean.A random sample of 130 full grown lobsters have a mean weight of 21 ounces is the standard deviation of 3.0 ounces. Construct a 98% confidence interval for the population mean.
To construct a confidence interval for estimating the population mean, we will use the formula:
Confidence interval = sample mean ± (critical value * standard deviation / square root of the sample size)
First, let’s calculate the critical value
To construct a confidence interval for estimating the population mean, we will use the formula:
Confidence interval = sample mean ± (critical value * standard deviation / square root of the sample size)
First, let’s calculate the critical value. Since we want a 98% confidence interval, the remaining area outside the interval would be (100% – 98%) / 2 = 1%.
Next, we need to find the corresponding z-score for a 1% area in each tail. Using a standard normal distribution table or a calculator, we find that the critical value for a 1% area is approximately 2.33.
Now, we can substitute the given values into the formula:
Confidence interval = 21 ± (2.33 * 3.0 / √130)
Calculating the standard error (standard deviation divided by the square root of the sample size):
Standard error = 3.0 / √130 ≈ 0.262
Substituting the standard error into the confidence interval formula:
Confidence interval = 21 ± (2.33 * 0.262)
Calculating the confidence interval:
Confidence interval = 21 ± 0.610
Rounded to the same number of decimal places as the sample mean (21), the 98% confidence interval for the population mean is approximately (20.390, 21.610).
More Answers:
Understanding Sampling Error in Statistical Analysis | Causes, Effects, and Mitigation StrategiesDetermining Minimum Sample Size for Estimating Population Mean | A Math-based Approach
Determining the Critical Z Value | Calculation and Explanation