Solve the problem for the compound events.A combination lock has 3 dials with 10 numbers per dial. How many possible combinations of numbers could be set to open the lock?
To find the number of possible combinations of numbers for the lock, we need to multiply the number of choices for each dial since each dial has 10 numbers
To find the number of possible combinations of numbers for the lock, we need to multiply the number of choices for each dial since each dial has 10 numbers.
Since there are 3 dials, there are 10 choices for the first dial, 10 choices for the second dial, and 10 choices for the third dial.
Therefore, the total number of possible combinations is calculated by multiplying the number of choices for each dial:
10 * 10 * 10 = 1000
Thus, there are 1000 possible combinations of numbers that could be set to open the lock.
More Answers:
How to Divide 46 by 53: Step-by-Step Division ProcessHow to Simplify the Fraction 46/109: Step-by-Step Guide and Explanation
Learn How to Simplify the Fraction 116/121 using the GCD and Euclidean Algorithm
Error 403 The request cannot be completed because you have exceeded your quota. : quotaExceeded