A two-digit number is chosen at random. What is the probability that the chosen number is a multiple of 7?1/101/911/9012/9013/90
Answer:13/90Explanation:There are 90 two-digit numbers (all integers from 10 to 99). Of those, there are 13 multiples of 7: 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98.
There are 90 two-digit numbers that can be chosen at random. To be a multiple of 7, the number must end in 7 or 1 (since 2 x 7 = 14 and 3 x 7 = 21 both end in 1).
There are 13 numbers that end in 7 (17, 27, 37…97) and 12 numbers that end in 1 (11, 21, 31…91) for a total of 25 possible numbers that are multiples of 7.
Therefore, the probability of choosing a multiple of 7 from the 90 two-digit numbers is 25/90, which simplifies to 5/18.
Therefore, the correct answer is 5/18.
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