Proving the Equivalence of ¬(¬p) and p in Mathematics: Step-by-Step Analysis

¬(¬p) ≡ p

To prove the given statement ¬(¬p) ≡ p, we need to show that the left-hand side (LHS) of the equation is equivalent to the right-hand side (RHS)

To prove the given statement ¬(¬p) ≡ p, we need to show that the left-hand side (LHS) of the equation is equivalent to the right-hand side (RHS).

Let’s break down the statement step by step:

LHS: ¬(¬p)
¬(¬p) means the negation of the negation of p. To simplify this expression, we can use the double negation law, which states that ¬(¬q) ≡ q. Applying this law to our expression, we can simplify ¬(¬p) to p:

LHS: ¬(¬p) => p

RHS: p
The RHS is simply p. Since the RHS is already p, there is nothing to simplify further.

Now we can compare the LHS and RHS:

LHS: p
RHS: p

Since the LHS is equal to the RHS, we can conclude that ¬(¬p) ≡ p.

More Answers:

Understanding the Equivalence of p ∧ F ≡ Fp ∨ T ≡ T: A Mathematical Analysis
The Logical Equivalence Between p ∧ ¬p and Fp ∨ ¬p: A Step-by-Step Breakdown
Proving logical equivalence: p ∧ p ≡ pp ∨ p ≡ p

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