∫(1/u)du=
To find the integral of (1/u) du, we can use the power rule of integration
To find the integral of (1/u) du, we can use the power rule of integration. According to the power rule, the integral of x^n dx, where n is any real number except -1, is (x^(n+1))/(n+1) + C, where C is the constant of integration.
In our case, 1/u can be seen as u^(-1). So, using the power rule, the integral of (1/u) du is (u^(-1+1))/(-1+1) + C = (u^0)/0 + C.
But, dividing by 0 is undefined. Therefore, the integral of (1/u) du is undefined.
In summary, the integral of (1/u) du is undefined because dividing by 0 is not valid.
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