lim x->0 sinx/x
To evaluate the limit of sinx/x as x approaches 0, we can use the concept of a trigonometric limit
To evaluate the limit of sinx/x as x approaches 0, we can use the concept of a trigonometric limit.
Let’s consider the function f(x) = sin(x)/x. When we plug in x = 0 directly into the function, we get an indeterminate form of 0/0, which cannot be evaluated directly.
To overcome this limitation, we can use a trigonometric identity. The limit we want to evaluate can be written as:
lim x->0 sin(x)/x = lim x->0 sin(x)/x * (1/sin(x))
Using the trigonometric identity sinθ/θ = 1 for θ ≠ 0, we can substitute θ = x:
lim x->0 sin(x)/x = lim x->0 1/sin(x)
Now, let’s analyze the limit of 1/sin(x) as x approaches 0. As x approaches 0, sin(x) also approaches 0. We know that sin(0) = 0. Therefore, 1/sin(x) diverges as x approaches 0, meaning it does not have a finite limit.
Hence, the limit of sinx/x as x approaches 0 is undefined.
Note: This result is often referred to as an “undefined limit” or “indeterminate form” since it does not yield a specific numeric value.
More Answers:
The Quotient Rule | Differentiating Rational Functions and Avoiding Division by ZeroMastering Calculus | Understanding and Applying the Power Rule for Differentiation
Derivative of Cot(x) | Explanation and Formula Using Quotient Rule