Derivative of csc(x)
To find the derivative of csc(x), we can start by expressing csc(x) in terms of sine:
csc(x) = 1/sin(x)
Now, to find the derivative of csc(x), we can use the quotient rule
To find the derivative of csc(x), we can start by expressing csc(x) in terms of sine:
csc(x) = 1/sin(x)
Now, to find the derivative of csc(x), we can use the quotient rule. The quotient rule states that if we have a function f(x) = g(x)/h(x), then the derivative is given by:
f'(x) = (g'(x)*h(x) – g(x)*h'(x))/(h(x))^2
In this case, g(x) = 1 and h(x) = sin(x). Let’s find the derivatives of g(x) and h(x):
g'(x) = 0 (since g(x) = 1, the derivative is 0)
h'(x) = cos(x) (this is the derivative of sin(x), which is cos(x))
Now, we can substitute these values into the quotient rule formula:
f'(x) = (0*sin(x) – 1*cos(x))/(sin(x))^2
Simplifying further:
f'(x) = -cos(x)/(sin(x))^2
Since f(x) = csc(x), we can rewrite the derivative as:
csc'(x) = -cos(x)/(sin(x))^2
Therefore, the derivative of csc(x) is -cos(x)/(sin(x))^2.
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