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  • John Rhodes
  • June 21, 2023
  • Calculus

Mastering The Product Rule: How To Differentiate The Product Of Two Functions

d/dx[uv]= vu’+uv’ The formula to differentiate the product of two functions is given by the product rule, which states: d/dx[uv] = u * dv/dx + v *...
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  • John Rhodes
  • June 21, 2023
  • Calculus

The Derivative Of A Constant: Why D/Dx[C] = 0

d/dx[c]= 0 The derivative of a constant c with respect to x is zero. This is because a constant value does not change as x changes, and...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Mastering The Power Rule: The Derivative Of X With Respect To X In Calculus

d/dx[x]= 1 1 The derivative of x with respect to x is 1, as the derivative measures the instantaneous rate of change of a function with respect...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Mastering The Chain Rule: How To Differentiate The Natural Logarithm Function Lne(X)

d/dx[lne(x)]= 1/x*x’ To differentiate the natural logarithm function, lne(x), we can use the chain rule: d/dx[lne(x)] = 1/x * d/dx[x] Since the derivative of x with respect...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Learn How To Find The Derivative Of E^X With Respect To X Using The Rule Of Exponential Functions

d/dx[e^x]= e^x To find the derivative of e^x with respect to x, we can use the rule that states: d/dx[e^x] = e^x This is because the derivative...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Mastering Derivatives Of Logarithmic Functions: A Step-By-Step Guide

d/dx[loga(x)]= 1/x(ln(a)) To find the derivative of loga(x), we will use the formula: d/dx[loga(x)] = 1/(x * ln(a)) Where ln(a) is the natural logarithm of a. Proof:...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Learn How To Find The Derivative Of A^X Using The Chain Rule In Math

d/dx[a^x]= a^x*ln(a) To find the derivative of a function of the form a^x with respect to x, we can use the chain rule. Let y = a^x,...
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  • John Rhodes
  • June 21, 2023
  • Calculus

Discover The Derivative Of Sin^-1(X) – Simplified Explanation And Formula

d/dx[sin^-1(x)]= 1/sqrt(1-x^2) To find the derivative of sin^-1(x), we first need to use the inverse property of trigonometric functions and express sin^-1(x) in terms of the inverse...
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