(1/u ln a)(du/dx)
d/dx log a u
To solve this problem, we need to use the chain rule of calculus, which states that if we have a function g(u) where u is a function of x, then:
d/dx [g(u)] = g'(u) * du/dx
In this case, we can see that we have a function f(u) = ln a, where u is a function of x. Using the chain rule, we can write:
d/dx [ln a/u] = (1/u) * du/dx (since the derivative of ln a is 0)
Now we can substitute our expression for d/dx [ln a/u] into the original problem:
(1/u ln a)(du/dx) = (1/ln a) * (1/u) * du/dx
This is our final answer.
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