d/dx [ tan(f(x)) ]
sec²(f(x))*f'(x)
Using the chain rule, we can differentiate this function as follows:
Let u = f(x), then we have:
y = tan(u)
We can write: y = tan[f(x)]
Using the chain rule, we obtain:
dy/dx = sec^2[f(x)] * f'(x)
Therefore, the derivative of tan(f(x)) is sec^2(f(x)) times the derivative of f(x).
d/dx [ tan(f(x))] = sec^2(f(x)) * f'(x)
More Answers:
[next_post_link]