limit as x approaches 0: 1-cosx/x
To find the limit as x approaches 0 for the given expression, we can apply L’Hôpital’s rule
To find the limit as x approaches 0 for the given expression, we can apply L’Hôpital’s rule.
L’Hôpital’s rule states that if the limit of f(x)/g(x) as x approaches a (where a can be a finite value or infinity) is an indeterminate form (such as 0/0 or infinity/infinity), then the limit of the derivative of f(x) divided by the derivative of g(x) is equivalent to the original limit.
In this case, we have the limit as x approaches 0 of (1 – cos(x))/x.
Since this expression evaluates to the indeterminate form 0/0 as x approaches 0, we can use L’Hôpital’s rule.
Taking the derivative of the numerator and the denominator, we have:
(1 – cos(x))’ = 0 – (-sin(x)) = sin(x)
x’ = 1
Now we can rewrite our limit using the derivatives:
lim(x→0) (1 – cos(x))/x = lim(x→0) (sin(x))/1
As x approaches 0, sin(x) approaches 0. Therefore, the limit simplifies to:
lim(x→0) (sin(x))/1 = 0/1 = 0
Hence, the limit as x approaches 0 of (1 – cos(x))/x is 0.
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