derv (ln u)
(u’)/u
To find the derivative of ln(u), where u is a function of some variable x.
Using the chain rule of differentiation, we have:
d/dx [ln(u)] = (d/du [ln(u)]) (du/dx)
Now, d/du [ln(u)] = 1/u, and du/dx is simply the derivative of the function u with respect to x.
Therefore, we can rewrite the derivative of ln(u) as:
d/dx [ln(u)] = (1/u) (du/dx)
So, the final answer is (1/u) (du/dx).
More Answers:
The Derivative Of The Reciprocal Trigonometric Function Csc(X) For Better Calculus PerformanceHow To Find The Derivative Of Tan(X) Using The Quotient Rule And Chain Rule.
Calculus: The Derivative Of Sin(X) Explained With Trigonometry
Error 403 The request cannot be completed because you have exceeded your quota. : quotaExceeded