∫(e^u)du
To solve the integral of e^u with respect to u, we can apply a basic integration technique known as integration by substitution
To solve the integral of e^u with respect to u, we can apply a basic integration technique known as integration by substitution.
Let’s denote the integral of e^u with respect to u as I. We can rewrite the integral as:
∫(e^u)du = I
Now, let’s choose a substitution that simplifies the integral. In this case, we can set u equal to a new variable, let’s say v:
u = v
Differentiating both sides of this equation with respect to v, we have:
du/dv = 1
Solving for du, we get:
du = dv
Now, we substitute back into the original integral to express everything in terms of v:
I = ∫(e^v)du
Notice that we now have an integral in terms of v instead of u. But since du = dv, we can substitute this into the integral as well:
I = ∫(e^v)dv
At this point, we can easily evaluate the integral. The integral of e^v with respect to v is simply e^v plus a constant of integration. Therefore:
I = e^v + C
Finally, we substitute back the original variable u for v:
I = e^u + C
So, the integral of e^u with respect to u is e^u plus a constant of integration (C).
More Answers:
Understanding Integration | Using Trigonometric Identity to Integrate CosineFinding the Antiderivative | Integrating 1/u using Logarithmic Function
Mastering the Definite Integral | A Step-by-Step Guide for Evaluating ∫kf(u)du