lim x->0 sinx/x
To find the limit of sinx/x as x approaches 0, we can use the limit definition and the trigonometric identity:
lim x->0 sinx/x = lim x->0 (sinx)/(x) * (1/sinx)
Since sinx/x is an indeterminate form (it evaluates to 0/0 at x=0), we can apply L’Hopital’s Rule to simplify the expression
To find the limit of sinx/x as x approaches 0, we can use the limit definition and the trigonometric identity:
lim x->0 sinx/x = lim x->0 (sinx)/(x) * (1/sinx)
Since sinx/x is an indeterminate form (it evaluates to 0/0 at x=0), we can apply L’Hopital’s Rule to simplify the expression. Taking the derivative of the numerator and denominator separately:
lim x->0 (cosx)/(1) = 1
Therefore, the limit of sinx/x as x approaches 0 is equal to 1.
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