lim theta->0 1 – cos(theta) / theta = ___________________
To find the limit of the given expression, we can use a trigonometric identity and apply a well-known limit
To find the limit of the given expression, we can use a trigonometric identity and apply a well-known limit. Let’s start by using the identity:
1 – cos(theta) = 2sin^2(theta/2)
Substituting this into the expression, we have:
lim theta->0 (2sin^2(theta/2)) / theta
Next, we can divide the numerator and denominator by theta/2:
lim theta->0 (2sin^2(theta/2)) / (theta/2) * (theta/2)
Now, let’s use a known limit that as theta approaches 0, sin(theta)/theta approaches 1. Based on this, we can rewrite the expression as follows:
lim theta->0 (2(sin(theta/2))^2) / (theta/2) * (theta/2)
= lim theta->0 (2(2sin(theta/2)cos(theta/2))^2) / (theta/2) * (theta/2)
= lim theta->0 (8sin^2(theta/2)cos^2(theta/2)) / (theta/2) * (theta/2)
= lim theta->0 (8sin^2(theta/2)) / (theta/2) * (theta/2) * (cos^2(theta/2))
= lim theta->0 (8sin^2(theta/2)) / (theta/2) * (theta/2)
= lim theta->0 8(sin(theta/2)/ (theta/2))^2
= 8(1)^2
= 8
So, the limit of the expression as theta approaches 0 is 8.
More Answers:
The Importance of Differentiability in Calculus and its ApplicationsUnderstanding the Derivative of a Constant | Why is it Always Zero?
How to Find the Derivative of a Sum or Difference of Two Functions | Sum and Difference Rules Explained