d/dx cscx
To find the derivative of the function y = csc(x), we can use the quotient rule
To find the derivative of the function y = csc(x), we can use the quotient rule.
The quotient rule states that if we have a function in the form y = f(x)/g(x), then its derivative is given by:
dy/dx = (f'(x) * g(x) – f(x) * g'(x)) / (g(x))^2.
Here, f(x) = 1 and g(x) = sin(x), since csc(x) is equal to 1/sin(x). Taking the derivatives of the numerator and denominator, we get:
f'(x) = 0 (since the derivative of a constant is zero)
g'(x) = cos(x) (the derivative of sin(x) is cos(x))
Now, we can substitute these values into the quotient rule formula:
dy/dx = (0 * sin(x) – 1 * cos(x)) / (sin(x))^2
Simplifying further, we have:
dy/dx = -cos(x) / sin^2(x)
We can also rewrite this as:
dy/dx = -cot(x) / sin(x)
Therefore, the derivative of y = csc(x) is -cot(x) / sin(x).
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