Which point is an x-intercept of the quadratic function f(x) = (x – 4)(x + 2)?(-4, 0)(-2, 0)(0, 2)(4, -2)
To find the x-intercepts of a quadratic function, we need to solve for the values of x when f(x) equals 0
To find the x-intercepts of a quadratic function, we need to solve for the values of x when f(x) equals 0. In the given function f(x) = (x – 4)(x + 2), let’s set f(x) equal to zero.
0 = (x – 4)(x + 2)
To find the values of x, we can set each factor equal to zero and solve for x separately:
x – 4 = 0 or x + 2 = 0
Solving the first equation, we add 4 to both sides:
x = 4
Solving the second equation, we subtract 2 from both sides:
x = -2
Therefore, the x-intercepts of the quadratic function f(x) = (x – 4)(x + 2) are x = 4 and x = -2. A point on the x-axis represents an x-intercept, so the coordinates of the x-intercepts are (-4, 0) and (-2, 0).
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