Solve for a when the function f(x) = a(x +2)² -1 passes through the point (0,0)
To solve for a when the function f(x) = a(x + 2)² – 1 passes through the point (0,0), we need to find the value of a that satisfies this condition
To solve for a when the function f(x) = a(x + 2)² – 1 passes through the point (0,0), we need to find the value of a that satisfies this condition.
Let’s substitute the x and y values of the point (0,0) into the function:
f(0) = a(0 + 2)² – 1
0 = a(2)² – 1
0 = 4a – 1
Now, we can solve this equation for a. Add 1 to both sides:
1 = 4a
Next, divide both sides by 4:
1/4 = a
Therefore, the value of a that satisfies the condition is a = 1/4.
Hence, when a = 1/4, the function f(x) = (1/4)(x + 2)² – 1 passes through the point (0,0).
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