lim x-> ∞ (1 + (1/x)) ^x
To find the limit of the given expression as x approaches infinity, let’s analyze it step by step
To find the limit of the given expression as x approaches infinity, let’s analyze it step by step.
The expression is:
lim x-> ∞ (1 + (1/x))^x
Let’s start by recognizing that the expression is of the indeterminate form “∞^0”. Therefore, one approach is to convert it into the form “e^(∞ * ln(1 + (1/x)))”.
Next, we can use the fact that ln(a^b) = b * ln(a) to simplify the expression:
= lim x-> ∞ e^(x * ln(1 + (1/x)))
Now, let’s consider the term ln(1 + (1/x)). As x approaches infinity, 1/x approaches zero. So, we can replace 1/x with 0 in the expression:
= lim x-> ∞ e^(x * ln(1 + 0))
Since ln(1) is equal to 0, we have:
= lim x-> ∞ e^0
Remember that e^0 is equal to 1. Therefore, the final result is:
= 1
Hence, the limit of (1 + (1/x))^x as x approaches infinity is 1.
More Answers:
Math Simplification | Simplifying the Expression 1 + cot^2x Using the Cotangent IdentityUnderstanding the Derivative | Calculating Rates of Change and Slope in Mathematics
Integration by Parts | Explained with Examples