lim theta->0 1 – cos(theta) / theta = ___________________
0
To evaluate the limit:
lim theta->0 1 – cos(theta) / theta
We can use L’Hopital’s rule or the trigonometric limit:
lim theta->0 sin(theta) / theta = 1
First, we can simplify the expression by multiplying both numerator and denominator by (1+cos(theta)):
(1-cos(theta)) / theta * (1+cos(theta)) / (1+cos(theta))
= (1 – cos^2(theta)) / (theta * (1 + cos(theta)))
= sin^2(theta) / (theta * (1 + cos(theta)))
Now, we can substitute sin(theta) / theta = 1:
lim theta->0 sin^2(theta) / (theta * (1 + cos(theta)))
= lim theta->0 (sin(theta) / theta)^2 / (1 + cos(theta))
= 1^2 / (1+1)
= 1/2
Therefore, the limit as theta approaches 0 of (1 – cos(theta)) / theta is 1/2.
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