What is the start value of the equation y = 3(1/2)^x
The equation you provided, y = 3(1/2)^x, represents an exponential function
The equation you provided, y = 3(1/2)^x, represents an exponential function. In this equation, the number 1/2 is the base of the exponential function, and x represents the exponent. The value of x can be any real number, positive or negative.
To find the start value of the equation, we need to determine the y-value when x is at its lowest possible value. Since x can be any real number, we would need to find the limit as x approaches negative infinity.
As x approaches negative infinity, the term (1/2)^x approaches zero. This is because as x becomes more and more negative, the value of (1/2)^x becomes smaller and smaller. However, since the coefficient 3 is multiplied by (1/2)^x, even if this term approaches zero, it would still influence the overall value of y.
Therefore, when x is at its lowest possible value (negative infinity), the term (1/2)^x becomes zero and the equation simplifies to y = 3 * 0 = 0.
Hence, the start value of the equation y = 3(1/2)^x is 0.
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