## lim theta->0 sin(theta) / theta = ___________________

### 1

The limit of sin(theta) / theta as theta approaches 0 is equal to 1.

To see why this is the case, we can use the fact that sin(theta) can be written as a Taylor series expansion centered around 0:

sin(theta) = theta – (theta^3 / 3!) + (theta^5 / 5!) – (theta^7 / 7!) + …

Dividing both sides by theta and taking the limit as theta approaches 0, we get:

lim theta->0 sin(theta) / theta = [1 – (theta^2 / 3!) + (theta^4 / 5!) – (theta^6 / 7!) + …] / 1

As theta approaches 0, each term in the expansion approaches 0, except for the first term which approaches 1. Therefore, the limit of sin(theta) / theta as theta approaches 0 is equal to 1.

##### More Answers:

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