The value of the derivative f’ at x = 1 is (**hint: imagine drawing a tangent line at x = 1)
The value of the derivative f’ at x = 1 can be determined by imagining drawing a tangent line to the graph of the function at x = 1
The value of the derivative f’ at x = 1 can be determined by imagining drawing a tangent line to the graph of the function at x = 1. The slope of this tangent line will represent the value of the derivative at that point.
To find the value of the derivative at x = 1, we need to calculate the slope of the tangent line at that point. This can be done by taking the derivative of the function f(x) and plugging in the value x = 1.
Let’s consider an example, say we have the function f(x) = 3x^2 – 2x + 1. To find the derivative, we apply the power rule. The derivative of x^n, where n is a constant, is given by n*x^(n-1).
So, applying the power rule, we find that f'(x) = 6x – 2.
Now, to find the value of the derivative at x = 1, we substitute x = 1 into the derivative function f'(x).
f'(1) = 6(1) – 2 = 6 – 2 = 4.
Therefore, the value of the derivative f’ at x = 1 is 4.
This means the slope of the tangent line to the graph of the function f(x) at x = 1 is 4.
More Answers:
Calculating the Integral of sin x | Techniques and UnderstandingCalculating the Left Riemann Sum Approximation for ∫101f(x)ⅆx Using Four Subintervals
Calculating the Right Riemann Sum for the Integral ∫(831+x)^(1/2)dx using Divide and Multiply Method