Let f be the function given by f(x)=x2e−x. It is known that ∫10f(x)ⅆx=0.160603. If a midpoint Riemann sum with two intervals of equal length is used to approximate ∫10f(x)ⅆx, what is the absolute difference between the approximation and ∫10f(x)ⅆx ?
To find the absolute difference between the midpoint Riemann sum approximation and the exact value of the integral, we need to follow these steps:
Step 1: Find the midpoint Riemann sum approximation
To find the absolute difference between the midpoint Riemann sum approximation and the exact value of the integral, we need to follow these steps:
Step 1: Find the midpoint Riemann sum approximation.
Step 2: Calculate the exact value of the integral.
Step 3: Find the absolute difference between the two.
Step 1: Midpoint Riemann Sum Approximation
To approximate the integral using a midpoint Riemann sum with two intervals of equal length, we divide the interval from 1 to 0 into two subintervals of equal length. Let’s denote the width of each interval as Δx. In this case, Δx = (1-0)/2 = 0.5.
Now, we evaluate the function at the midpoint of each subinterval and multiply it by the width Δx. Then, we sum up these values.
f(x) = x^2 * e^(-x)
Approximation using midpoint Riemann sum:
sum = f(0.25 * Δx) + f(0.75 * Δx)
= f(0.25 * 0.5) + f(0.75 * 0.5)
= f(0.125) + f(0.375)
Now, let’s calculate f(0.125) and f(0.375) using the given function:
f(0.125) = (0.125)^2 * e^(-0.125) ≈ 0.015279
f(0.375) = (0.375)^2 * e^(-0.375) ≈ 0.058243
Summing these values:
sum ≈ 0.015279 + 0.058243
≈ 0.073522
Step 2: Exact Value of the Integral
The given integral is:
∫(1 to 0) f(x) dx = 0.160603
Step 3: Absolute Difference
Now, let’s find the absolute difference between the midpoint Riemann sum approximation and the exact value:
Absolute difference = |Approximation – Exact value|
= |0.073522 – 0.160603|
= |-0.087081|
= 0.087081
Therefore, the absolute difference between the midpoint Riemann sum approximation and the exact value of the integral is approximately 0.087081.
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