lim x->0 1-cosx/x
To find the limit of the expression (1-cos(x))/x as x approaches 0, we can apply the concept of L’Hôpital’s rule
To find the limit of the expression (1-cos(x))/x as x approaches 0, we can apply the concept of L’Hôpital’s rule. L’Hôpital’s rule states that if we have an indeterminate form of the type 0/0 or ∞/∞ when finding a limit, we can differentiate the numerator and denominator separately until we get a result that is no longer indeterminate.
Let’s apply L’Hôpital’s rule to this problem:
lim x->0 (1-cos(x))/x
Since both the numerator (1-cos(x)) and the denominator (x) go to 0 as x approaches 0, we have an indeterminate form of 0/0.
Now, let’s differentiate the numerator and denominator separately:
lim x->0 sin(x)/1
Differentiating the numerator, we get cos(x). Differentiating the denominator, we get 1.
So, the limit becomes:
lim x->0 cos(x)/1
Now, we can substitute x = 0 into the expression:
cos(0)/1 = 1/1 = 1
Therefore, the limit of (1-cos(x))/x as x approaches 0 is equal to 1.
More Answers:
Understanding the Inverse Cosecant Function and How to Solve for Its ValuesUsing L’Hôpital’s Rule to Evaluate the Limit as x Approaches 0 of sin(bx)/x
Exploring the Limit of sin(x)/x as x Approaches 0 using the Squeeze Theorem