d/dx logax
To find the derivative of the function log_a(x) with respect to x, where “a” is the base of the logarithm:
The logarithmic function log_a(x) can be rewritten as ln(x) / ln(a), where ln(x) represents the natural logarithm of x (base e) and ln(a) represents the natural logarithm of a (base e)
To find the derivative of the function log_a(x) with respect to x, where “a” is the base of the logarithm:
The logarithmic function log_a(x) can be rewritten as ln(x) / ln(a), where ln(x) represents the natural logarithm of x (base e) and ln(a) represents the natural logarithm of a (base e).
Now, let’s find the derivative of ln(x) / ln(a) with respect to x using the quotient rule:
Step 1: Find the derivative of the numerator (ln(x)).
Using the chain rule, the derivative of ln(x) with respect to x is 1/x.
Step 2: Find the derivative of the denominator (ln(a)).
Since ln(a) is a constant (a is a constant), its derivative is 0.
Step 3: Apply the quotient rule.
Using the quotient rule, the derivative of ln(x) / ln(a) is:
[ (derivative of numerator) * ln(a) – (numerator) * (derivative of denominator) ] / (denominator)^2
Plugging in the values we found in Steps 1 and 2, we get:
[ (1/x) * ln(a) – ln(x) * 0 ] / (ln(a))^2
Simplifying further, we have:
(1/x) * ln(a) / (ln(a))^2
Now, since ln(a) is a constant, let’s express it as a single term:
(1/x) * (1 / ln(a)) / ln(a)
Finally, combining like terms, we get:
1 / (x * ln(a))
Therefore, the derivative of log_a(x) with respect to x is 1 / (x * ln(a)).
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