Find sum of first 30 odd natural numbers ( 1+3+…+59)
To find the sum of the first 30 odd natural numbers, we can use the formula for the sum of an arithmetic series
To find the sum of the first 30 odd natural numbers, we can use the formula for the sum of an arithmetic series.
The formula for the sum of an arithmetic series is given by:
Sn = (n/2)(a + l)
where Sn is the sum of the series, n is the number of terms, a is the first term, and l is the last term.
In this case, we are given the first term a = 1 and the last term l = 59.
Since we are dealing with odd natural numbers, we can find the number of terms using the formula:
n = (l – a)/2 + 1
Substituting the values into the formula, we get:
n = (59 – 1)/2 + 1
n = 58/2 + 1
n = 29 + 1
n = 30
Now we can substitute the values of n, a, and l into the sum formula:
Sn = (30/2)(1 + 59)
Sn = 15(60)
Sn = 900
Therefore, the sum of the first 30 odd natural numbers is 900.
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