## (x-5)²

### To find the expanded form of (x-5)², we need to multiply the expression (x-5) by itself

To find the expanded form of (x-5)², we need to multiply the expression (x-5) by itself.

Using the distributive property, we have:

(x-5)² = (x-5)(x-5)

To simplify this, we can use the FOIL method, which stands for:

– First: multiply the first terms of each binomial.

– Outer: multiply the outer terms of each binomial.

– Inner: multiply the inner terms of each binomial.

– Last: multiply the last terms of each binomial.

Applying the FOIL method, we get:

(x-5)(x-5) = x*x + x*(-5) + (-5)*x + (-5)*(-5)

= x² – 5x – 5x + 25

= x² – 10x + 25

Therefore, the expanded form of (x-5)² is x² – 10x + 25.

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