2 (3x + 1) = 7x – 5
To solve the equation 2(3x + 1) = 7x – 5, we will follow these steps:
Step 1: Distribute the 2 to both terms inside the parentheses:
6x + 2 = 7x – 5
Step 2: Move all the x terms to one side of the equation by subtracting 6x from both sides:
2 = 7x – 6x – 5
Simplifying the equation further, we get:
2 = x – 5
Step 3: Isolate the x term by adding 5 to both sides:
2 + 5 = x – 5 + 5
Simplifying the equation further, we get:
7 = x
So, the solution to the equation is x = 7
To solve the equation 2(3x + 1) = 7x – 5, we will follow these steps:
Step 1: Distribute the 2 to both terms inside the parentheses:
6x + 2 = 7x – 5
Step 2: Move all the x terms to one side of the equation by subtracting 6x from both sides:
2 = 7x – 6x – 5
Simplifying the equation further, we get:
2 = x – 5
Step 3: Isolate the x term by adding 5 to both sides:
2 + 5 = x – 5 + 5
Simplifying the equation further, we get:
7 = x
So, the solution to the equation is x = 7.
That means when we substitute x = 7 back into the original equation, both sides should be equal:
2(3(7) + 1) = 7(7) – 5
Simplifying both sides of the equation:
2(21 + 1) = 49 – 5
2(22) = 44
44 = 44
Since both sides are equal, our solution is correct.
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