Master Foil Method In Expanding (X-6)(X-3) To Simplify Quadratic Expressions

(x-6)(x-3)

x²-9x+18

To expand (x-6)(x-3), we can use the FOIL method, which stands for First, Outer, Inner, Last.

First: Multiply the first term of each factor (x*x) to get x^2
Outer: Multiply the outer terms of each factor (x*-3) to get -3x
Inner: Multiply the inner terms of each factor (-6*x) to get -6x
Last: Multiply the last term of each factor (-6*-3) to get 18

Putting these terms all together, we get:

(x-6)(x-3) = x^2 – 3x – 6x + 18

Simplifying this expression by combining like terms, we get:

(x-6)(x-3) = x^2 – 9x + 18

Therefore, the expanded form of (x-6)(x-3) is x^2 – 9x + 18.

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