(x+1)(x-7)
x²-6x-7
To expand the expression (x+1)(x-7), we can use the distributive property of multiplication. We multiply each term in the first factor by each term in the second factor, then add the resulting products.
So, we have:
(x+1)(x-7) = x(x-7) + 1(x-7)
Now, we can use the distributive property again on each of these two terms:
x(x-7) = x^2 – 7x
1(x-7) = x – 7
Putting them back together, we have:
(x+1)(x-7) = x^2 – 7x + x -7
Simplifying by combining like terms, we get:
(x+1)(x-7) = x^2 – 6x – 7
Therefore, the expanded form of (x+1)(x-7) is x^2 – 6x – 7.
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