## Find sum of the first eight terms of the geometric series; 3+6+12+…

### To find the sum of the first eight terms of a geometric series, we need to use the formula for the sum of a geometric series:

S = a * (r^n – 1) / (r – 1)

In this formula, “S” represents the sum of the series, “a” represents the first term of the series, “r” represents the common ratio, and “n” represents the number of terms we want to find the sum of

To find the sum of the first eight terms of a geometric series, we need to use the formula for the sum of a geometric series:

S = a * (r^n – 1) / (r – 1)

In this formula, “S” represents the sum of the series, “a” represents the first term of the series, “r” represents the common ratio, and “n” represents the number of terms we want to find the sum of.

In the given series, the first term (a) is 3, and to find the common ratio (r), we can take any two consecutive terms and divide them:

Common ratio (r) = 6 / 3 = 2

Now, let’s substitute these values into the formula to find the sum of the first eight terms:

S = 3 * (2^8 – 1) / (2 – 1)

= 3 * (256 – 1) / 1

= 3 * 255

= 765

Therefore, the sum of the first eight terms of the given geometric series, 3+6+12+…, is 765.

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