Find sum of first 30 odd natural numbers ( 1+3+…+59)
To find the sum of the first 30 odd natural numbers, you can use the formula for the sum of an arithmetic series
To find the sum of the first 30 odd natural numbers, you can use the formula for the sum of an arithmetic series. In an arithmetic series, the terms are in a sequence where the difference between any two consecutive terms is constant.
In this case, the sequence of odd numbers has a common difference of 2. Therefore, we can use the formula for the sum of an arithmetic series:
Sn = (n/2)(2a + (n-1)d)
where Sn represents the sum of the series, a is the first term, n is the number of terms, and d is the common difference.
Given that the first term a = 1, the number of terms n = 30, and the common difference d = 2, we can substitute these values into the formula:
Sn = (30/2)(2(1) + (30-1)(2))
= 15(2 + 29*2)
= 15(2 + 58)
= 15(60)
= 900
Therefore, the sum of the first 30 odd natural numbers is 900.
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