Find sum of first 30 odd natural numbers ( 1+3+…+59)
To find the sum of the first 30 odd natural numbers, we can use the formula for the sum of an arithmetic series:
Sn = (n/2)(2a + (n-1)d)
Where:
Sn is the sum of the arithmetic series,
n is the number of terms,
a is the first term, and
d is the common difference
To find the sum of the first 30 odd natural numbers, we can use the formula for the sum of an arithmetic series:
Sn = (n/2)(2a + (n-1)d)
Where:
Sn is the sum of the arithmetic series,
n is the number of terms,
a is the first term, and
d is the common difference.
In this case, the first term (a) is 1, the number of terms (n) is 30, and the common difference (d) is 2 because we are adding odd numbers. Therefore, we can plug in these values into the formula:
Sn = (30/2)(2(1) + (30-1)(2))
= 15(2 + 29(2))
= 15(2 + 58)
= 15(60)
= 900
So, the sum of the first 30 odd natural numbers is 900.
More Answers:
How to Find the nth Term of an Arithmetic Sequence: A Step-by-Step GuideUnderstanding the Concept of the Common Ratio in Geometric Sequences: A Fundamental Math Guide
Understanding Common Differences and Arithmetic Sequences in Mathematics
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