x²+11x+18
(x+9)(x+2)
The expression x²+11x+18 is a quadratic expression, which means it is of degree 2 and can be written in the form of ax²+bx+c, where a, b, and c are constants.
Here, a = 1, b = 11, and c = 18.
To factor this expression, we need to find two numbers that add up to 11 and multiply to 18. We can start by listing the factor pairs of 18:
1 x 18
2 x 9
3 x 6
Out of these factor pairs, we can see that 3 and 6 add up to 9. Therefore, we can rewrite 11x as 3x + 8x and factor the expression as:
x²+11x+18 = x²+3x+8x+18
= (x²+3x) + (8x+18)
= x(x+3) + 2(4x+9)
= (x+3)(x+2)(factor 4x+9 as 2(2x+9/2))
Therefore, the expression x²+11x+18 can be factored as (x+3)(x+2)(2x+9/2).
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