Find sum of the first eight terms of the geometric series; 3+6+12+…
To find the sum of a geometric series, we need to know the first term (a), the common ratio (r) between consecutive terms, and the number of terms (n)
To find the sum of a geometric series, we need to know the first term (a), the common ratio (r) between consecutive terms, and the number of terms (n).
In this case, the first term is 3, and each term is obtained by multiplying the previous term by 2. So, the common ratio (r) is 2.
We need to find the sum of the first eight terms (n = 8).
The formula for the sum of a geometric series is given by:
Sn = a * (r^n – 1) / (r – 1)
Substituting the given values, we have:
S8 = 3 * (2^8 – 1) / (2 – 1)
Simplifying the expression further:
S8 = 3 * (256 – 1) / 1
S8 = 3 * 255
S8 = 765
Therefore, the sum of the first eight terms of the geometric series 3+6+12+… is 765.
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