Calculating the First Five Terms of the Sequence Defined by f(n) = 2n – 8 in Math

What are the first five terms of the sequence defined by the given function?f(n) = 2n − 8

To find the first five terms of the sequence defined by the function f(n) = 2n – 8, we need to substitute different values of n into the function and calculate the corresponding output values

To find the first five terms of the sequence defined by the function f(n) = 2n – 8, we need to substitute different values of n into the function and calculate the corresponding output values.

Let’s substitute the values of n from 1 to 5 into the function:

For n = 1:
f(1) = 2(1) – 8
= 2 – 8
= -6

For n = 2:
f(2) = 2(2) – 8
= 4 – 8
= -4

For n = 3:
f(3) = 2(3) – 8
= 6 – 8
= -2

For n = 4:
f(4) = 2(4) – 8
= 8 – 8
= 0

For n = 5:
f(5) = 2(5) – 8
= 10 – 8
= 2

Therefore, the first five terms of the sequence defined by f(n) = 2n – 8 are: -6, -4, -2, 0, and 2.

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