the limit as n approaches zero of (1+n)¹/ⁿ is
lim n→0 (1+n)¹/ⁿ = e.
To solve this limit problem, we can use L’Hopital’s rule or the natural logarithm approach.
Using L’Hopital’s rule:
Taking the natural logarithm of the expression and using logarithmic properties, we get
lim n→0 ln(1+n) / n
Now applying L’Hopital’s rule by taking the derivative of the numerator and denominator with respect to n,
= lim n→0 (1 / (1+n)) / 1
= (1 / (1+0)) / 1
= 1
Therefore, lim n→0 (1+n)¹/ⁿ = e¹ = e.
Using the natural logarithm approach:
We can use the fact that
lim n→0 (1+n)¹/ⁿ = lim n→0 e^(ln(1+n) / n)
Now, applying the limits property of exponentials, we get
= e^lim n→0 ln(1+n) / n
And again, using L’Hopital’s rule,
= e^(lim n→0 1 / (1+n))
= e^(1/1)
= e
Therefore, lim n→0 (1+n)¹/ⁿ = e.
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