John Rhodes, Math Teacher at Senioritis.io

John Rhodes
June 21, 2023
Calculus

The Relationship Between Acceleration And Velocity: The Equation For Velocity With Respect To Time

The velocity is the integral of acceleration the acceleration function with respect to time. The equation for velocity is given by: v(t) = ∫ a(t) dt +...

John Rhodes
June 21, 2023
Calculus

The Power Rule Of Integration: Antiderivatives Of X^R Explained (R ≠ -1)

∫x^r dx = [x^(r+1) / (r +1) ] + C Assuming that r is not equal to -1, the antiderivative of x^r with respect to x is:...

John Rhodes
June 21, 2023
Calculus

Learn How To Evaluate Integral Of Cos(X) Using Integration By Substitution

∫cosx dx = sinx + C The integral of cos(x) can be evaluated using integration by substitution: Let u = sin(x); then du/dx = cos(x) and dx...

John Rhodes
June 21, 2023
Calculus

How To Integrate Sin(X) Using The Chain Rule And Substitution Method?

∫sinx dx = -cosx + C ∫sin(x) dx = -cos(x) + C where C is the constant of integration. This is because the derivative of -cos(x) is...

John Rhodes
June 21, 2023
Calculus

Master The Integration Of Sec²X With Substitution Method: Antiderivative Of Sec²X Simplified

∫sec^2x dx = tanx + C The integral of sec^2x can be calculated using integration by substitution method. Let u = tan x, then du/dx = sec^2x...

John Rhodes
June 21, 2023
Calculus

Step-By-Step Guide: Finding The Antiderivative Of Csc^2X Using U-Substitution And The Power Rule Of Integration

∫csc^2x dx = -cotx + C To integrate ∫csc^2x dx, we use u-substitution. Let u = cot(x) and du = -csc^2x dx. Then: ∫csc^2x dx = ∫-du/u^2...

John Rhodes
June 21, 2023
Calculus

How To Integrate Sec(X)Tan(X) Using U-Substitution

∫secxtanx dx = secx + C To integrate ∫secxtanx dx, we can use u-substitution. Let u = secx + tanx, then du/dx = secxtanx + sec^2x. Now,...

John Rhodes
June 21, 2023
Calculus

Learn How To Solve The Integral Of Csc X Cot X Dx With U-Substitution

∫cscxcotx dx = -cscx + C We can solve this integral by using u-substitution with u = csc x and du = -csc x cot x dx:...