1 + cot^2x =
To solve the equation 1 + cot^2x = ?, we need to simplify the expression on the left side
To solve the equation 1 + cot^2x = ?, we need to simplify the expression on the left side.
First, let’s write the equation in terms of sine and cosine functions. Remember that cot(x) is equal to cos(x) divided by sin(x):
1 + cot^2x = 1 + (cos^2x / sin^2x)
Next, let’s find a common denominator for the two terms in the numerator:
1 + (cos^2x / sin^2x) = (sin^2x / sin^2x) + (cos^2x / sin^2x)
Now, combine the terms in the numerator:
(sin^2x + cos^2x) / sin^2x
Remember that sine squared plus cosine squared equals 1, according to the Pythagorean identity:
1 / sin^2x
Recall that the reciprocal of sine is cosecant (csc):
csc^2x
So, 1 + cot^2x simplifies to csc^2x.
More Answers:
Theorem 3.5: Test for Increasing and Decreasing Functions – A Comprehensive Guide to Determine Function Behavior on Specified IntervalsA Guide to Using the Integration by Parts Formula in Calculus with an Example
Simplifying the Expression 1 + tan^2x: Applying the Pythagorean Identity and Revealing the Equivalent Form of sec^2x
Error 403 The request cannot be completed because you have exceeded your quota. : quotaExceeded