x^2 + 15x + 36
To analyze the given expression, we need to understand that it represents a quadratic equation in the form of ax^2 + bx + c, where a = 1, b = 15, and c = 36
To analyze the given expression, we need to understand that it represents a quadratic equation in the form of ax^2 + bx + c, where a = 1, b = 15, and c = 36.
To find the solutions or roots of the quadratic equation, we can use the quadratic formula:
x = (-b ± √(b^2 – 4ac)) / (2a)
Substituting the values for a, b, and c into the quadratic formula, we get:
x = (-(15) ± √(15^2 – 4(1)(36))) / (2(1))
x = (-15 ± √(225 – 144)) / 2
x = (-15 ± √81) / 2
x = (-15 ± 9) / 2
Now, we have two solutions:
x1 = (-15 + 9) / 2 = -6 / 2 = -3
x2 = (-15 – 9) / 2 = -24 / 2 = -12
Therefore, the solutions to the quadratic equation x^2 + 15x + 36 are x = -3 and x = -12.
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